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TASK (i): Find time-domain equations for a parallel LC resonant circuit An LC resonant circuit is...
For the following resonant series circuit shown in fig. 1, find : - Quality factor, Q. - Bandwidth, B. - The voltage across the capacitor. - The voltage across the inductor. - The voltage across the resistor. L = 4.7 mH C = 0.001uF S R = 470 VIN-1 V Fig. 1 Resonant series circuit
Vout TL074 10kS2 10 mH Figure 2. LC bandpass resonant filter 4. In Part 2 of this lab, you will construct a "resonant" LC bandpass filter (Fig. 2). The filter will only allow signals at the resonant frequency to pass through. For example, if you input a 1kHz square wave into a 5kHz resonant bandpass filter, the resulting output will be a sinusoid at 5kHz. From Prelab Part 1, we know that a square wave can be represented as an...
SC 9) (5 marks) Figure 9 represents a simple circuit in the time domain. The impedance of a capacitor in the complex frequency domain is Z = 1 and for an inductor Z = sl. If the complex frequency describing the circuit in Fig. 9 is s = -150 +j100 s-1, determine the time domain voltage vs(t) (provided by the source) which corresponds to a frequency-domain voltage V2 = 52-250 V. i(t) 21 12 + V1 + Vs 100 mH...
2r() V and the capacitor initially stores zero energy. (a) Write the time-domain loop equation in terms of the current io). b) Obtain the s-domain representation of this integral equation. (c Solve for io. 50. The s-domain representation of the voltage source in Fig. 14.16 is V, (s)- İ V. The initial voltage across the capacitor, defined using the 200 mF i() passive sign convention in terms of the current i, is 4.5 V. (a) Write the time- domain integral...
do not use s domain method ,use only differential equation 3. In the circuit shown, switch 1 has been closed for a long time before it is opened at t 0, and switch 2 has been opened for a long time before it is closed at t = 0. SW2 sw, 0.5Ω R2 1(2 A, 20 A i(t) 0.5 H a. Find the initial voltage v(O)- Vo across the capacitor and initial current through the inductor (0) lo at t...
ng off a long time. Find 6) For the following circuit, the voltage source turns on a time zero after bei (a) at t 0+ the inductor current i(O+) and its rate of change, (b) at t = 0+ the capacitor voltage vo-) and its rate of change, du (Do not write a differential equation or solve for voltage or current as functions of time.) dt t0+ 4012 10.2 211(1) A 10u() V tz 0 lot) 1O Carm
In an LC circuit, at time zero, there is a non-zero charge in the capacitor and a non-zero current. As the circuit oscillates, the energy in the circuit can be found with: The inductance of the inductor Starting current att=0 The starting voltage at t-0 The capacitance of the capacitor
please help!! LC Circuit 1 а A circuit is constructed with two capacitors and an inductor as shown. The values for the capacitors are: C1 = 175 pF and C2 = 399 pF. The inductance is L = 254 mH. At time t =0, the current through the inductor has its maximum value I (0) = 262 mA and it has the direction shown. 0000 1) What is wo, the resonant frequency of this circuit? 179 radians/s Submit Your submissions:...
Consider the circuit depicted in Fig. 2. The switch SW1 has been closed for a long time before it is opened at time t = 0. The switch SW2 has been open for a long time before it is closed att = 0.1 (sec). i) Find the initial current I(0) flowing in the inductor and the initial voltage V(0) across the capacitor. ii) Find the voltage V(t) across the capacitor and the current I(t) through the inductor for 0 ≤ t ≤...
2-a)-RLC components connected in series in a circuit supplied by a variable dc voltage can be described by the following differential equations: di(t) wherei@ is the loop current and V1(t) İs the voltage drop across the inductor.+' The voltage drop across the resistor is given by Ohm's law vR(t) R i(t) and the voltage drop across the capacitor vc(t) is given by i(t) dt For a series circuit ye)t vit)t velt) v(t) where v(t) is applied voltage: Figure 3: RLC...