A proton travels with a speed of 3.00 x 10 m/s at an angle of 34.0°...

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A proton travels with a speed of 3.00 x 10 m/s at an angle of 34.0° with the direction of a magnetic field of 0.400 T in the

Answer 1

Answer #1

Press charge =te -19 = 1.6*10 no = 3.00 x 106 mis Speed Magnetic field B=0.400T Angle between en magnetic field B and vectoci

Answer 2

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