Question

6. Draw both the 1,2- and the 1,4-addition products of the following substrate. Circle the kinetic product (2 pts.). HBE (1 ) 7. Construct an inscribed polygon in the circle provided to illustrate the molecular orbitals for the cycloheptatrienyl anion. Illustrate the relative energies of all the molecular orbitals, label bonding and anti-bonding and assuming this species is planar, assess whether it is non-aromatic, aromatic, or anti-aromatic. Explain why (2 pts.).

Answer 1

Solve Givenj HBO (tequivalent) Products - Mechanism. This is "Electrophilic addition on a kene" - Br@ Protonation of alkene. (3 carbocation) - Resonante stabilised Cé carbocation) attack of Nucleophile X Br (kinetis 'product) (1,2- addition product) l - Br (Theo modynamic product) (14- addition product). Notes In product; more stable al kene_is_ the thermodynamis. Products as Scanned with ATTIS

- (17: Molecular orbitals for cyclobeptatoienytanies.. Selve! ------..Stoucture of cycloheptatojenyl mionis. Anti bonding orbitals Bonding ভচছাত্ব: e cycloheptatienyl amion has Eight (8) II electrons: The_molecular orbital of cyclobeptatrienyl anion is shown with the relative energies of Bonding odbitals and anti-bonding_Orbitals. 67T- electrons are filled with bonding orbitals while 211electrons gre_filled with anti-bonding Orbitals. This molecue.js pleman but have IT-electrons in Anti-bonding_08 bitals. Thus it is Amti aromatic Cyclo-heptatsieny) anion_is_Anti-cromatic ca Ścannedraith CamScanner