How many moles of electrons are required to produce 95.3 g of aluminum metal from a sample of molten aluminum fluoride?
AlF3 ---- > Al3+ + 3F-
Al3+ + 3e- ---> Al
Number of moles of Al metal = 95.3 g / 27.0 g.mol^-1 = 3.53 mole
1 mole of Al metal requires 3 mole of electron
3.53 mole of Al metal will requie
= 3.53 mole of Al metal *(3 mole of electron/1 mole of Al metal)
= 10.59 mole of electron will be required.
Therefore, the number of moles of electrons required are 10.59 mole
How many moles of electrons are required to produce 95.3 g of aluminum metal from a...
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