Question

Please answer the three questions below:

1)

Below is a binomial distribution for n-7 and p 0.4. 0.25 0.2 0.15 0.1 0.05 Number of Successes Binomial Distribution Calculate the mean of the binomial distribution. Preview [two decimal accuracy]

2)

3.)

Answer 1

The mean and standard deviation of binomial distribution is np and sqrt(npq).

1)

Given that n = 7; p = 0.4

Mean = np = 7*0.4 = 2.8

$\mu =2.80$

2) Given that n = 6 p= 0.6

In binomial distribution p + q = 1

q = 1 - p = 1-0.6 =0.4

Standard deviation = $\sqrt{npq} = \sqrt{6*0.6*0.4} =\sqrt{1.44} = 1.2$

$\sigma =1.200$