Question

Find the electric field vector at point P for the charge configurations shown below. Simplify your final answer. a) 9 + a b a -9 b) b 9 a -9 a

Answer 1

To solve the problem we have simply used the resolving the electric filed components in x and y direction and then we get the net electric field by vector addition of the fields components.

a ) = 22 +62 re a Ę Coso E coso x م o ya E a E, sino E sino - a beſarth? E = kq we have resolved the components, Now we find &, and to Kq a²+62 E = K9 KG since E=E₂ a216² so E, caso and Ecoso cancels eachother. E =-E sind ŷ - EzSindý 2 we get a Sinda E = -26, sind È - 2 kq a²+6² Saz? 8= – 2kq a a a244² y (K= k= arco m urto (22+62 3/2 -aq a Two 42) = 2qa » dipole moment Ytto (a²+2 ² ² AO = Þ aga 40to (2²+52 / Utto (a²th? ½

b ) E sind & sind TON r= Ja²12 13 b Ecoso E, coso E = 102462 YEz ol # ng 2 ; &z=Kq 42 80 E = = R - a²t6² E, a so and Elso will cancel eachother - Goslay+f2 Ez = &, sind ý + E sind ŷ - Ez ŷ Since E = q so E = 28 sine 9 - Ez E = 2KG a²t6² E = 2Kq b ġ (a²th 2 3/2 sind ŷ - Kq 4² Kg b² 80 1) a R Q b - kq b2 Ja (2²1673/2