Question

Week 17- Concept Questions When you have a firm understanding of the thermochemical solution cycle (hint go read Ch 11.2 if you have not done so already) you can predict whether a solute will readily dissolve in a solvent. Draw a diagram to represent the enthalpy components of Sodium Chloride dissolving in water (an exothermic process) and draw a diagram to represent the enthalpy components of decane-C Hy, dissolving in water (an endothermic process). Based off of the Holn for each mixture which one is more likely to produce a solution? Hint: you do not need to use any numbers or math. Make sure to label each enthalpy component.

Answer 1

Dissolution of sodium chloride in water is an exothermic reaction which means that on dissolving sodium chloride to water energy will release. Lattice enthalpy to break sodium chloride atoms apart is compensated by this released energy. And hence it is soluble in water.

ANSWER- * Sodium Chloride (NaCl) in water → NaCl is readily soluble in water Heart Hotter than Surroundings Heat EXOTHERMIC DH Negative * Decane (C o Hag) in water Decane is insoluble in water Cooler than Sux roundings & Heat Heat ENDOTHERMIC DH Positive * Sodium Chloride is more likely to form solution with water. Since Decane is insoluble in water, it will not Solution with water.

Dissolution of decane in water is endothermic reaction which means energy is required from surrounding. Decane is insoluble in water but it's soluble in organic solvents.