what is the degeneracy (W) for C6H5Br?
the two highest binding molecular orbitals (pi)2 and (pi)3are degenerate. in mono substituted benzenes this degeneracy is removed. it is determined by photo electron spectroscopy.
When benzene C6H6 reacts with bromine Br2, bromobenzene C6H5Br is obtained: C6H6 + Br2 --> C6H5Br + HBr (balanced already) When 15.0 g of benzene reacts with excess Br2, 0.19 mole of bromobenzene C6H5Br was produced? IF the actual yield was 42.3 g of C6H5Br produced, Calculate the percent yield.
4, what is the origin of quantum state degeneracy. (5%)
a. In a few sentences, explain the concept of degeneracy in regards to the resonant modes of a rectangular membrane. In your answer, be sure to emphasize how the aspect ratio relates to degeneracy. What aspect ratio specifically emphasizes degeneracy?
(4) Provide the synthetic route for the following reaction. C6H5Br C6H5COOH (5) Provide the synthetic route for the following reaction. -CH, -CH2COOH
Hello, can you help me provide the synthetic route for the below reaction? Thank you. C6H5Br C6H3COOH
The degeneracy of a system of NA identical molecules A in a three-dimensional box has the form g = V^ (NA) f(EA,NA). If we add NB more molecules of a diferent substance B, keeping the volume constant, what is the new equation for the degeneracy?
3. (a) What is the degeneracy of the 3d infinite square well problem with box sizes L,-3 L3 3, and energy E-90. (use natural units, that is set hbar 1 and 2 m1) (b) List the states too. , L2-3 :
Calculate : i) degeneracy of the ground state of a particle in a linear (1-dimensional) box ii) Degeneracy of the ground state of a particle in a cubic (3-dimensional) box The answer is both same number of degeneracy. WHY? please showing calculation and explain
to find the degeneracy of excited state of nitrogen atom
1. (3 pts) What is the degeneracy of J=0 and J=1 for a linear, symmetric, and spherical rotor? For each rotor, give the complete set of quantum numbers for each state. (Each state should have a unique set of quantum numbers.)