Question

An outstretched arm is holding an apple with a mass of 150 g, as shown in the figure above. The arm is 30 degrees below the
horizontal, and the apple is held 27 cm from the shoulder joint. What is the torque around the shoulder joint caused by the apple? (answer is in Nm)

30

0 0
Add a comment Improve this question Transcribed image text
Answer #1

The torque is given by

T= F * r * sin x

Here, x is the angle between the force acting and the distance from the point.

30 + x = 90

x = 90 - 30 = 60

So T = ( 0.150 * 9.8 ) * 0.27 * sin 60 = 1.27 N-m

Add a comment
Know the answer?
Add Answer to:
An outstretched arm is holding an apple with a mass of 150 g, as shown in...
Your Answer:

Post as a guest

Your Name:

What's your source?

Earn Coins

Coins can be redeemed for fabulous gifts.

Not the answer you're looking for? Ask your own homework help question. Our experts will answer your question WITHIN MINUTES for Free.
Similar Homework Help Questions
  • 3. The figure shows an outstretched arm with a mass of 4.2 kg. The arm is...

    3. The figure shows an outstretched arm with a mass of 4.2 kg. The arm is 56 cm long, and its center of gravity is 21 cm from the shoulder. The hand at the end of the arm hold a mass of 6.0 kg. (a) What is the torque about the shoulder due to the weights of the arm and the 6.0 kg mass? (b) If the arm is held in position by the deltoid muscle, whose force on the...

  • When you hold your arm outstretched, it's supported primarily by the deltoid muscle.

    When you hold your arm outstretched, it's supported primarily by the deltoid muscle. The given figure shows a case in which the deltoid exerts a 67 N force at 15 degrees to the horizontal. If the force-application point is 18 cm horizontally from the shoulder joint, what torque does the deltoid exert about the shoulder?

  • A man is holding an 8.00-kg vacuum cleaner at arm's length, a distance of 0.550 m...

    A man is holding an 8.00-kg vacuum cleaner at arm's length, a distance of 0.550 m from his shoulder What is the torque on the shoulder joint if the arm is held at 30.0degree below the horizontal? 21.6 Nm 2.20 Nm 4.40 Nm 12.6 Nm 37.4 Nm

  • The total mass of the arm shown in (Figure 1) is 3.5 kg . The location...

    The total mass of the arm shown in (Figure 1) is 3.5 kg . The location of the center of mass of the arm is shown, FM is the force exerted by the deltoid muscle on the upper arm, and FJ is the normal force from the shoulder joint on the upper arm. Part A Determine the magnitude of the force required from the deltoid muscle to hold up the outstretched arm in the position shown. Part B Suppose this...

  • please answer C, and confirm that A and B are correct. (if you can) Fa Fm...

    please answer C, and confirm that A and B are correct. (if you can) Fa Fm (17.0" from ) a) (10 pts) Calculate the torque, about the Z-axis through the shoulder joint, due to the force of gravity on the dumbbell, Fa. (2, 23x9.80) dercos (43) Tdt d. Fa - (0.545)(COS(43)) td-(0.645X21.854) d-0.3986 m Td 11.91 Nm b) (10 pts) Calculate the torque, about Z-axis through the shoulder joint, due to the force of gravity on the mass of the...

  • please answer in full detail 4. Use the drawing below as a model of forces involved...

    please answer in full detail 4. Use the drawing below as a model of forces involved in holding an outstretched arm stationary, let Fu model the "deltoid muscle, which provides tension at an angle of to the bones and _cm represent the center of mass of the arm. X_M12 cm x cm 24 cm mass of the arm - 3.3 kg 015 a. the shoulder joint labeled in the above figure but decomposed into it's - and y. components in...

  • A woman lifts a 3.6-kg barbell in each hand with her arm in a horizontal position...

    A woman lifts a 3.6-kg barbell in each hand with her arm in a horizontal position at the side of her body and holds it there for 3 s (see the figure below). What force does the deltoid muscle in her shoulder exert on the humerus bone while holding the barbell? The deltoid attaches 13 cm from the shoulder joint and makes a 13? angle with the humerus. The barbell in her hand is 0.55 m from the shoulder joint,...

  • Part A A 75.0 kg weight lifter is doing arm raises using a 7.50 kg weight...

    Part A A 75.0 kg weight lifter is doing arm raises using a 7.50 kg weight in her hand. Her arm pivots around the elbow joint, starting 40.0° below the horizontal (See the figure(Figure 1).) Biometric measurements have shown that both forearms and the hands together account for 5.75 % of a person's weight. Since the upper arm is held vertically, the biceps muscle always acts vertically and is attached to the bones of the forearm 5.50 cm from the...

  • Constants A 71.0 kg weight lifter is doing arm raises using a 7.50 kg weight in...

    Constants A 71.0 kg weight lifter is doing arm raises using a 7.50 kg weight in her hand. Her arm pivots around the elbow joint, starting 40.0 below the horizontal. (See the figure(Figure 1).) Biometric measurements have shown that both forearms and the hands together account for 6.40 % of a person's weight. Since the upper arm is held vertically, the biceps muscle always acts vertically and is attached to the bones of the forearm 5.50 cm from the elbow...

  • A 75.0 kg weight lifter is doing arm raises using a 7.50 kg weight in her...

    A 75.0 kg weight lifter is doing arm raises using a 7.50 kg weight in her hand. Her arm pivots around the elbow joint, starting 40.0 below the horizontal. (See the figure (Figure 1).) Biometric measurements have shown that both forearms and the hands together account for 5.75% of a person's weight. Since the upper arm is held vertically, the biceps muscle always acts vertically and is attached to the bones of the forearm 5.50 cm from the elbow Part...

ADVERTISEMENT
Free Homework Help App
Download From Google Play
Scan Your Homework
to Get Instant Free Answers
Need Online Homework Help?
Ask a Question
Get Answers For Free
Most questions answered within 3 hours.
ADVERTISEMENT
ADVERTISEMENT
ADVERTISEMENT