A fictitious element, ζ, has 4 isotopes. The mass numbers of three of them are 130, 132, and 133. Their respective natural abundances are 10, 12, and 45%. What is the mass number of the fourth isotope, if the A-value of element ζ in the Periodic Table is listed as 132.91?
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A fictitious element, ζ, has 4 isotopes. The mass numbers of three of them are 130,...
QUESTION 3 A fictitious element is composed of isotopes A and B with masses of 61.9887 and 64.9846 amu respectively. The average atomic mass of the element is 64.52 amu. What can you conclude about the natural abundances of the two isotopes? O The natural abundance of isotope A must be greater than that of isotope B OThe natural abundance of isotope B must be greater than that of isotope A. O The natural abundances of both isotopes must be...
4. An element has two naturally occurring isotopes. The mass numbers of these isotopes are 111 amu and 113 amu, with natural abundances of 25% and 75%, respectively. Calculate the atomic mass for this element. 6 pts
In an imaginary universe, the element is composed of three isotopes. These isotopes, their exact masses, and percent abundances are listed in the table below. Calculate the average atomic mass. Percent Isotope Mass Abundance 2K 65.77 23.97 66.27 24.94 "K 67.72 51.09 SK
The atomic mass of magnesium on the periodic table is based on three isotopes, ^24_12Mg, ^25_12Mg, and^26_12Mg. If a fourth isotope is discovered, it would change the abundances of all the others, and it would change the molar mass listed on the periodic table. Calculate the molar mass of magnesium, based on the masses and abundances given below.[^23_12Mg mass = 22.9862, abundance 22.50%] [^24_12Mg mass = 23.9850, abundance 62.49%] [^25_12Mg mass = 24.9858, abundance 10.20%]^26_12Mg mass = 25.9826, abundance 4.810%]
An element has two naturally-occurring isotopes. The mass numbers of these isotopes are 111 amu and 113 amu, with natural abundances of 75% and 25%, respectively. Calculate its average atomic mass.
An element has two naturally-occurring isotopes. The mass numbers of these isotopes are 125 amu and 127 amu, with natural abundances of 80% and 20%, respectively. Calculate its average atomic mass. Report your answer to 1 decimal place. -------- amu
The element X has three naturally occurring isotopes. The masses (amu) and % abundances of the isotopes are given in the table below. The average atomic mass of the element is _ _amu. Isotope Abundance (%) Mass (amu) 221X 74.22 220.90 12.78 220.00 2187 13.00 218.10 2207 219.70 220.34 220.43 219.00 33.333
< Question 4 of 17 > Suppose that a fictitious element, X, has two isotopes: 59X (59.015 amu) and "x (62.011 amu). The lighter isotope has an abundance of 75.7%. Calculate the average atomic mass of the element X average atomic mass:
Most elements occur naturally as a mix of different isotopes. An element's atomic mass is the weighted average of the isotope masses. In other words, it is an average that takes into account the percentage of each isotope. For example, the two naturally occurring isotopes of boron are given here The atomic mass of boron is calculated as follows: (10.0 times 0.199) + (11.0 times 0.801) = 10.8 amu Because the heavier isotope is more abundant the atomic mass a...
The element carbon has two naturally occurring isotopes. The isotopic masses and abundances of these isotopes are shown in the table below. Isotope 12c isotopic mass (amu) Abundance (%) 12.00 13.00 98.93 1.07 Calculate the average atomic mass of carbon to two digits after the decimal point. Number = _______ amu