An element has two naturally-occurring isotopes. The mass numbers of these isotopes are 125 amu and 127 amu, with natural abundances of 80% and 20%, respectively. Calculate its average atomic mass. Report your answer to 1 decimal place.
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An element has two naturally-occurring isotopes. The mass numbers of these isotopes are 125 amu and...
An element has two naturally-occurring isotopes. The mass numbers of these isotopes are 111 amu and 113 amu, with natural abundances of 75% and 25%, respectively. Calculate its average atomic mass.
Enter your answer in the provided box. An element has two naturally occurring isotopes. The mass numbers of these isotopes are 109 amu and 111 amu, with natural abundances of 35% and 65%, respectively. Calculate its average atomic mass. Report your answer to 1 decimal place. amu
4. An element has two naturally occurring isotopes. The mass numbers of these isotopes are 111 amu and 113 amu, with natural abundances of 25% and 75%, respectively. Calculate the atomic mass for this element. 6 pts
The element carbon has two naturally occurring isotopes. The isotopic masses and abundances of these isotopes are shown in the table below. Isotope 12c isotopic mass (amu) Abundance (%) 12.00 13.00 98.93 1.07 Calculate the average atomic mass of carbon to two digits after the decimal point. Number = _______ amu
Calculate the atomic mass of element "X", if it has 2 naturally occurring isotopes with the following masses and natural abundances. X-45, 44.8776 amu, 32.88% X-47, 46.9443 amu, 67.12%
The element Oxygen consists of three naturally occurring isotopes with masses 15.949915, 16.999131, and 17.999159 amu. The relative abundances of these three isotopes are 99.76, 0.03800, and 0.2000 percent, respectively. From these data calculate the average atomic mass of Oxygen (in amu).
The element X has three naturally occurring isotopes. The masses (amu) and % abundances of the isotopes are given in the table below. The average atomic mass of the element is _ _amu. Isotope Abundance (%) Mass (amu) 221X 74.22 220.90 12.78 220.00 2187 13.00 218.10 2207 219.70 220.34 220.43 219.00 33.333
A fictitious element, Beaverium, has two naturally occurring isotopes. 285Bv has a mass of 284.67 amu and is 42.744% abundant. 288Bv has a mass of 287.73 amu and is 57.256% abundant. What is the average atomic mass (in amu) of Beaverium?
5) Calculate the atomic mass of an imaginary element X that has 3 naturally occurring isotopes with the following masses and natural abundances: 106.90509 amu 108.90476 amu 107.91536 amu 51.84% 38.46% 9.70% A) 106.80 amu B) 108 amu C) 107.77 amu D) 108.32 amu E) 107.8 amu
A hypothetical element X has 3 naturally occurring isotopes: 41.20% of 21X, with an atomic weight of 21.016 amu, 6.83% of 22X, with an atomic weight of 21.942 amu, and 51.97% of 24X, with an atomic weight of 23.974 amu. On the basis of these data, calculate the average atomic weight of element X. Report your answer to two decimal places.