Question

A given pipe having 250 mm diameter at section A and 500 mm diameter at section B carries petrol of specific gravity 0.89 at the flow rate of 270 l/s. The section B is at altitude of 14 m above section A. If the pressure of the petrol at section A and section B are 190 KPa and 150 KPa respectively. 1 - Calculate the Head Loss between the two sections; 2 - Change the unit flow rate in USA unit; 3 - Give your conclusion about the flow.

Answer 1

discharge = 8: 270 l/sec = 0.29 m/sec & dA = 0.25m I do = 0.5m VA = 0.27 = 5.5m/50 - #x0202 PA = 190kpa ZA: Po = 150 KPA ZB = 14m (1) To calculate head loss Total head at A = PA + ZA + VA Toil 190+ ot 0.89*9.8D - 23.3 m of Oil 2x9.81 Total head at B = PB + ZB + VB² 5 + 14+ 138 = 31.27m 0.89x9.81 2x9.81 of oil head loss = Total Head) - (Total head) A 31.27 - 23.3 Head loss = 7.97 m of oil) flow will occur from B to 4

(11) Change of flow wait in ft?re = 0.27m/ec. Im= 3.28 feet = 0.27X13:28,3 la = 9.527 ft /sec Conversion (iii) Flow conclusion y flow occurt from higher total head to lower total head. In this case the total Pressure head At B is higher than total Pressure head at A. so flow will occur from B → A.