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(b) Perform convolution to obtain the discreet if input x[n] = [1 3 2 1] and impulse response, h[n] signal output of y[n], [1

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Answer #1

b). Given

x[n]=[1\ 3\ 2 \1] \\ h[n]= [1 \ -4 \2]

The formula for convolution is given as :

y[n]=\sum_{-\infty}^{\infty}x[k]h[n-k]

applying this formula we obtail

y[0]=\sum_{-\infty}^{\infty}x[k]h[-k]= 1

y[1] x[k]h[1 - k] -1

y[2]=\sum_{-\infty}^{\infty}x[k]h[2-k]= -8

y[3]=\sum_{-\infty}^{\infty}x[k]h[3-k]= -1

y[4]=\sum_{-\infty}^{\infty}x[k]h[4-k]= 0

y[5]=\sum_{-\infty}^{\infty}x[k]h[5-k]= 2

c).

i). Number of samples = \frac{\text{total signal duration}}{\text{sampling duration}} = \frac{1000}{50\times 10^{-3}}= 20000

ii). Highest Frequency is the sampling frequency which is given by inverse of sampling duration i.e,

\text{Sampling rate}= \frac{1}{\text{Sampling duration}}=\frac{1}{50\times 10^{-3}} =20 \ Hz

iii).

. \text{frequency resolution}= \frac{\text{Sampling rate}}{\text{Number of samples}}=\frac{1}{50\times 10^{-3}\times 20000} \\=1 \times 10^{-3 } Hz

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