A toy rocket is fired at v0 = 40.7 m/s at an angle of ? = 72.3o
with respect to the horizontal on flat level ground. Assuming that
air resistance is negligible, what is its maximum height (H) and
how far (R) will the rocket have traveled in the horizontal
direction by the time it lands?
0.5*M*Vy^2 = M*g*H
H = Vy^2/2g = (V*sin72.3)^2/2g = (40.7*sin72.3)^2/(2*9.81) =76.62m
R = V^2*sin(2*72.3)/g = (40.7^2*sin(72.3*2))/9.8 = 97.92 m
v=40.7
H=(v*sintheta)^2/(2*g)
theta=72.3
g=9.8m/s^2
H=76.7m
R=v^2*sin(2*theta)/(2*g)
=48.95m
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