Question

4) that of a uniform' phere ( (8.6.12) whereas n = 2a2/5) is (8.6.13) Calculate the center of mass acceleration of the cylinder rolling down the inclined plane in Figure of contact as in Figure 8.5.2c. ng. Choose an axis O' that Solution: As previously explained, the choice of this axis satisfies condition 3 given in Section 8.5 and we can use Equation 8.6.2 di orqure acting about O' is No, = mg a sin θ why n

I thought i have to consider mgsin(theta) and friction force for net force to calculate No'.But in textbook it is not considered.

i dont know why.

Answer 1

Given that

The cylinder is rolling down on inclined plane without slipping.

That means, frictional force is Zero (f=0)

That's why Here Net Force N0=mg asin($\Theta$)