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tion 3 of 40 ) A voltaic cell employs the redox reaction: Zn (s) + Pb2+...
- Zn2+ Choose... Choose... (1pts) Identify the complete redox reaction for a ZnZn2+1|Cu2+1Cu cell. A. Zn(s)...
- Zn2+ Choose... Choose... (1pts) Identify the complete redox reaction for a ZnZn2+1|Cu2+1Cu cell. A. Zn(s) + Cu?+ (aq) (aq) + Cu(s) B. Zn(s) + Cu(s) → Zn2+ (aq) + Cu2+ (aq) C. Zn2+ (aq) + Cu(s) Zn(s) + Cu2+ (aq) D. Zn (s) + 2 Cu(s) — Zn2+ (aq) + 2 Cu2+ (aq) (1pts) Identify the complete redox reaction for a Zn/Zn2+||Pb2+1Pb cell. A. Zn (s) + Pb(s) Zn2+ (aq) + Pb2+ (aq) B. Zn2+ (aq) + Pb(s) Zn(s)...
A voltaic cell employs the following redox reaction: 2 Fe3+ (aq) + 3 Mg(s) + 2...
A voltaic cell employs the following redox reaction: 2 Fe3+ (aq) + 3 Mg(s) + 2 Fe (s) + 3 Mg²+ (aq) Calculate the cell potential at 25 °C under each of the following conditions. Part B [Fe3+] =1.3x103 Μ; [Mg2+] = 1.85 M ΡΟΙ ΑΣΦ 5 - 0 ΕΞΙ ? Ecell = - Part [Fe3+] = 1.85 M ; (Mg2+] = 1.3x10-3 M 1190 AM O O ? Ecell =
Candidate l: Zn(s) | Zn2+(aq,0.500 M) I Cu2+(aq, 1.00 M) Cu(s) Candidate 2: Pb(s) | Pb2+(aq,...
Candidate l: Zn(s) | Zn2+(aq,0.500 M) I Cu2+(aq, 1.00 M) Cu(s) Candidate 2: Pb(s) | Pb2+(aq, 0.500 M) || Cu2+(aq, 1.00 M) Cu(s) Candidate 3: Mg(s) | Mg2+(aq, 0.500 M) | Pb2+(aq, 1.00 M)| Pb(s) (a) 6 pts) Choose one of the candidate voltaic cells #1, #2, or #3. Draw a schematic cell diagram for the candidate voltaic cell of choice. Clearly label anode, cathode, electrodes, ions and their concentrations, salt bridge, and the flow of electrons. (b) (5 pts)...
A voltaic cell employs the following redox reaction: 2 Fe3+ (aq) + 3 Mg(s) + 2...
A voltaic cell employs the following redox reaction: 2 Fe3+ (aq) + 3 Mg(s) + 2 Fe (s) + 3 Mg2+ (aq) Calculate the cell potential at 25 °C under each of the following conditions. Part B You may want to reference (Pages 865 - 869) Section 19.6 while completing this problem. [Fe3+] = 2.5x10-3 M ; [Mg2+] = 2.85 M Express your answer in units of volts. ΟΙ ΑΣΦ ? Ecell V Submit Request Answer Part C [Fe3+] =...
Consider the reaction corresponding to a voltaic cell and its standard cell potential. cell Zn(s) +...
Consider the reaction corresponding to a voltaic cell and its standard cell potential. cell Zn(s) + Cu2+ (aq) + Cu(s) + Zn2+ (aq) E = 1.1032 V As What is the cell potential for a cell with a 2.573 M solution of Zn²+ (aq) and 0.1055 M solution of Cu²+ (aq) at 432.4 K?
A voltaic cell consists of a Pb/Pb2+ half-cell and a Cu/Cu2+ half-cell at 25°C. The initial...
A voltaic cell consists of a Pb/Pb2+ half-cell and a Cu/Cu2+ half-cell at 25°C. The initial concentrations of Pb2+ and Cu2+ are 0.0500 M. and 1.50 M, respectively. What is the initial cell potential? Hint: the standard potential of Pb2+ + 2e → Pb(s) is -0.130 and the standard potential of Cu2+ + 2e → Cu(s) is +0.340. Hint #2: Use [Cu2+] as the product and [Pb2+] as the reactant. Ecell = 0.044 Ecell = 0.383 Ecell = 0.426 Ecell...
A voltaic cell consists of a Pb/Pb2+ half-cell and a Cu/Cu2+ half-cell at 25 °C. The initial concentrations of Pb2+...
A voltaic cell consists of a Pb/Pb2+ half-cell and a Cu/Cu2+ half-cell at 25 °C. The initial concentrations of Pb2+ and Cu2+ are 0.0500 M and 1.50 M, respectively. What are the concentrations of Pb2+ and Cu2+ when the cell potential falls to 0.370 V? Cu2+ (aq) + Pb(s) + Cu(s) + Pb2+ (aq) Hint: [Pb2+] + [Cu2+] = (1.5M + 0.05M) = 1.55 M total Hint: the standard potential of Pb2+ + 2e → Pb(s) is -0.130 and the...
1.) For the complete balanced redox reaction below, what is the Eocell? Zn(s) + 2Cu+(aq) ⟶...
1.) For the complete balanced redox reaction below, what is the Eocell? Zn(s) + 2Cu+(aq) ⟶ 2Cu(s) + Zn2+(aq) Zn2+ + 2e- Zn(s) Eo = -0.76 V Cu+ + e- Cu(s) Eo = 0.52 A) -1.28 V B) +1.28 V C) 0.24 V D) -0.24 V E) +2.56 V 2.) For the redox reaction below, what is the Ecell if [Zn2+] = 0.072 M and [Cu+] = 1.27 M? T = 298 K Zn(s) + 2Cu+(aq) ⟶ 2Cu(s) + Zn2+(aq) Half Reactions:...
Question 8 0.5 pts A voltaic cell consists of a Pb/Pb2 half-cell and a Cu/Cu2* half-cell...
Question 8 0.5 pts A voltaic cell consists of a Pb/Pb2 half-cell and a Cu/Cu2* half-cell at 25 °c. The initial concentrations of Pb2 and Cu2* are 0.0500 M and 1.50 M, respectively. What is the initial cell potential? Hint: the standard potential of Pb2*+2e » Pb(s) is -0.130 and the standard potential of Cu2 + 2e -» Cu(s) is +0.340. Hint #2: Use [Cu2*] as the product and [Pb2'] as the reactant. Ecell 0.044 Ecell 0.383 Ecell 0.426 Ecell...
A voltaic cell employs the following redox reaction: 2Fe3+(aq)+3Mg(s)→2Fe(s)+3Mg2+(aq) Calculate the cell potential at 25 ∘C...
A voltaic cell employs the following redox reaction: 2Fe3+(aq)+3Mg(s)→2Fe(s)+3Mg2+(aq) Calculate the cell potential at 25 ∘C under each of the following conditions. You may want to reference (Pages 865 - 869) Section 19.6 while completing this problem. Part A standard conditions Express your answer in units of volts. Ecell = V Part B [Fe3+]= 1.2×10−3 M ; [Mg2+]= 1.70 M Express your answer in units of volts. Ecell = V SubmitRequest Answer Part C [Fe3+]= 1.70 M ; [Mg2+]=1.2×10−3 M...
- Zn2+ Choose... Choose... (1pts) Identify the complete redox reaction for a ZnZn2+1|Cu2+1Cu cell. A. Zn(s) + Cu?+ (aq) (aq) + Cu(s) B. Zn(s) + Cu(s) → Zn2+ (aq) + Cu2+ (aq) C. Zn2+ (aq) + Cu(s) Zn(s) + Cu2+ (aq) D. Zn (s) + 2 Cu(s) — Zn2+ (aq) + 2 Cu2+ (aq) (1pts) Identify the complete redox reaction for a Zn/Zn2+||Pb2+1Pb cell. A. Zn (s) + Pb(s) Zn2+ (aq) + Pb2+ (aq) B. Zn2+ (aq) + Pb(s) Zn(s)...
A voltaic cell employs the following redox reaction: 2 Fe3+ (aq) + 3 Mg(s) + 2 Fe (s) + 3 Mg²+ (aq) Calculate the cell potential at 25 °C under each of the following conditions. Part B [Fe3+] =1.3x103 Μ; [Mg2+] = 1.85 M ΡΟΙ ΑΣΦ 5 - 0 ΕΞΙ ? Ecell = - Part [Fe3+] = 1.85 M ; (Mg2+] = 1.3x10-3 M 1190 AM O O ? Ecell =
Candidate l: Zn(s) | Zn2+(aq,0.500 M) I Cu2+(aq, 1.00 M) Cu(s) Candidate 2: Pb(s) | Pb2+(aq, 0.500 M) || Cu2+(aq, 1.00 M) Cu(s) Candidate 3: Mg(s) | Mg2+(aq, 0.500 M) | Pb2+(aq, 1.00 M)| Pb(s) (a) 6 pts) Choose one of the candidate voltaic cells #1, #2, or #3. Draw a schematic cell diagram for the candidate voltaic cell of choice. Clearly label anode, cathode, electrodes, ions and their concentrations, salt bridge, and the flow of electrons. (b) (5 pts)...
A voltaic cell employs the following redox reaction: 2 Fe3+ (aq) + 3 Mg(s) + 2 Fe (s) + 3 Mg2+ (aq) Calculate the cell potential at 25 °C under each of the following conditions. Part B You may want to reference (Pages 865 - 869) Section 19.6 while completing this problem. [Fe3+] = 2.5x10-3 M ; [Mg2+] = 2.85 M Express your answer in units of volts. ΟΙ ΑΣΦ ? Ecell V Submit Request Answer Part C [Fe3+] =...
Consider the reaction corresponding to a voltaic cell and its standard cell potential. cell Zn(s) + Cu2+ (aq) + Cu(s) + Zn2+ (aq) E = 1.1032 V As What is the cell potential for a cell with a 2.573 M solution of Zn²+ (aq) and 0.1055 M solution of Cu²+ (aq) at 432.4 K?
A voltaic cell consists of a Pb/Pb2+ half-cell and a Cu/Cu2+ half-cell at 25°C. The initial concentrations of Pb2+ and Cu2+ are 0.0500 M. and 1.50 M, respectively. What is the initial cell potential? Hint: the standard potential of Pb2+ + 2e → Pb(s) is -0.130 and the standard potential of Cu2+ + 2e → Cu(s) is +0.340. Hint #2: Use [Cu2+] as the product and [Pb2+] as the reactant. Ecell = 0.044 Ecell = 0.383 Ecell = 0.426 Ecell...
A voltaic cell consists of a Pb/Pb2+ half-cell and a Cu/Cu2+ half-cell at 25 °C. The initial concentrations of Pb2+ and Cu2+ are 0.0500 M and 1.50 M, respectively. What are the concentrations of Pb2+ and Cu2+ when the cell potential falls to 0.370 V? Cu2+ (aq) + Pb(s) + Cu(s) + Pb2+ (aq) Hint: [Pb2+] + [Cu2+] = (1.5M + 0.05M) = 1.55 M total Hint: the standard potential of Pb2+ + 2e → Pb(s) is -0.130 and the...
Question 8 0.5 pts A voltaic cell consists of a Pb/Pb2 half-cell and a Cu/Cu2* half-cell at 25 °c. The initial concentrations of Pb2 and Cu2* are 0.0500 M and 1.50 M, respectively. What is the initial cell potential? Hint: the standard potential of Pb2*+2e » Pb(s) is -0.130 and the standard potential of Cu2 + 2e -» Cu(s) is +0.340. Hint #2: Use [Cu2*] as the product and [Pb2'] as the reactant. Ecell 0.044 Ecell 0.383 Ecell 0.426 Ecell...
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