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A hospital claims that the proportion, p, of full-term babies born in their hospital that weigh more than 7 pounds is 48%. In

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Answer #1

Test statistic Z

Z = ( p ^ - p)/sqrt [ p *(1-p)/n ]

Where p^ = 76/200 = 0.38

Z = ( 0.38 - 0.48)/Sqrt [ 0.48*0.52/200]

Z = -2.831

This is Test statistic value

Now critical values for a = 0.01 and two tailed test

Zcritical = Z​​​​​​a/2  = Z​​​​​​0.005

Zcritical = -2.58 ,

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