Sample size , n= 235
Sample proportion of babies who weigh more than 7 pounds , =114/235 = 0.4851
The null hypothesis, H0 : p =0.41
The alternative hypotehsis, H1 : p 0.41
The type of test statistc - one proportion z test
Test statistic , z=
=
= 2.341
P-value = 2 P(z < -2.34)
= 2 * [ 1- P(z < 2.34)]
= 2 * [ 1- 0.99036]
= 2* 0.00964
= 0.01928
Since the P-value is less than the significance level , hence we will reject the null hypothesis.
Hence we have enough evidence at 0.1 significance level to support the claim that the proportion of full term babies born in their hospital that weigh more than 7 pounds is 41%
No, we can not reject the calim that the proportion of full term babies born in their hospital that weigh more than 7 pounds is 41%
A hospital claims that the proportion, p, of full-term babies born in their hospital that weigh...
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