40.0 grams of water at 64.2C is added to 60.0 grams of water at 25.0C in...
40.0 grams of water at 64.2C is added to 60.0 grams of water at 25.0C in a calorimeter. The final temperature of this solution was found to be 39.6C. What is the heat capacity of the calorimeter?
Homework Answers
Specific heat of water= 4.184 J/gm.deg.c
heat is removed from water at 64.2 deg.c and this is added to water at 25 deg.c and calorimeter
hence heat removed from hot water= mass of water* specific heat of water* change in temperature = 40*4.184*(64.2-39.6) =4117 = mass of cold water* specific heat of cold water* change in temperature + calorimeter constant* change in temperature = 60*4.184*(39.6-25)+Calorimeter constant*(39.6-25)
Calorimeter constant = heat capacity of calorimeter = (4117-3665)/ (39.6-25)= 30.95 J/deg.c
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