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72.0 grams of an unknown metal at 95.0oC is added to 115.0 grams of water (cs...

72.0 grams of an unknown metal at 95.0oC is added to 115.0 grams of water (cs = 4.184 J/g•oC) at 21.0oC in an insulated container. If the final temperature of the metal and water is 27.3oC then what is the specific heat capacity (cs) of the metal?

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Answer #1

For the metal mars (na) = 72 gm. The change in temperature (t) = (95-27.3) °C = 67.7°C Lets assume the specific heatasi so he

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