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A 41.0 g block of an unknown metal is heated in a hot water bath to...

A 41.0 g block of an unknown metal is heated in a hot water bath to 100.0°C. When the block is placed in an insulated vessel containing 130.0 g of water at 25.0°C, the final temperature is 28.0°C. Determine the specific heat of the unknown metal. The cs for water is 4.18 J/g°C.
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Answer #1

(mcat) water - (mc DT) metal. 130g * 4.183/ac * (28-25) = 419 x cm* (100-28° 1630.2 = 2952 cm Im = 0.5523/9°c

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