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please include a pv diagram

6. One mole of an ideal gas does 3 000 J of work on its surroundings as it expands isothermally to a final pressure of 1.00 a
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Answer #1

A(Po, V. T= constt. Isothermal B(P1, V) →V (P-V Diagram)

(b) For given P = 1atm V = 25 litres N=1

using state equation for ideal gas = PV = NRT

T = PV/NR = 1e5*25e-3/8.314 = 300.7 K

(a) Now work done by the gas in an isothermal expansion is given by

W = NRT ln(V1/V0)

Hence,

V0 = V1*exp(-W/NRT) = 25*exp(-3/8.314*300.7) = 24.97 litres

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