Find the critical value for c = 0.95 and n =
10
solution
Degrees of freedom = df = n - 1 = 10- 1 = 9
At 0.95 confidence level the t is ,
=1 - 0.95 = 0.05
/
2= 0.05 / 2 = 0.025
t
/2,df = t0.025,9 =2.262 ( using student t
table)
Find the critical value for c = 0.95 and n = 10 Find the critical value...
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Determine the upper-tail critical value ta/2 in each of the following circumstances. a. 1-α-0.95, n-20 b. 1-a-0.99, n 20 c. 1-a-0.95, n 36 d. 1-α= 0.95, n=28 e. 1-α-0.90, n-51 (Round to four decimal places as needed.) t-1 (Round to four decimal places as needed.) c.t(Round to four decimal places as needed.) t (Round to four decimal places as needed.) e.t(Round to four decimal places as needed.)
Determine the upper-tail critical value tα/2 in each of the following circumstances.a.1−α=0.95, n=56d.1−α=0.95, n=64b.1−α=0.90, n=56e.1−α=0.99, n=22c.1−α=0.95, n=38
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