1.D
Potential energy = mgh
since potential energy depends on the height and height travelled is same for both.
2. B
I = moment of inertia = mR2 + mR2 = 2 mR2
3.
change in kinetic energy at bottom = kinetic energy at the top
(0.5) m (v22 - v12) = (0.5) m v2
(52 - 42) = v2
v = 3 m/s
4. A
vf = final velocity = 40
vi = initial velocity = - 30
m = mass = 0.140
t = time of contact = 0.002
F = m (vf - vi)/t = (0.140) (40 - (-30))/0.002 = 4900
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