In an elevator that conveniently has a scale, a lady of 65.0 kg mass, was happy to read 442 N for her weight on the scale. Determine
(a) the direction of the elevator’s acceleration.
(b) the magnitude of the elevator’s acceleration
here,
the mass of lady , m = 65 kg
the weight of lady , W = m * g
W = 65 * 9.81 N = 637.65 N
a)
as the apparent weight of lady is less than the weight of lady
the direction of acceleration of elevator must be Downwards
b)
let the magnitude of acceleration be a
the apparent weight , W' = 442 N = m * ( g - a)
442 = 65 * ( 9.81 - a)
solving for a
a = 3.01 m/s^2
the magnitude of acceleration is 3.01 m/s^2
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