Question

In he inde qenderdt assortment model, Leschttdilubnd nss Luiex tp 0s in Expen ewed a sianticant devicction But Mov raho elow ous ha DUu O-E ite Shot 13 White lo Led Sho Total 8lo potability
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Answer:

Phenotype

Observed(O)

Expected (E)

O-E

(O-E)2

(O-E)2/E

red, long

123

105

18

324.00

3.09

white, short

137

105

32

1024.00

9.75

white, long

74

105

-31

961.00

9.15

red, short

86

105

-19

361.00

3.44

Total

420

420

25.43

Chi-square value = 25.43

Degrees of freedom = number of catergories -1 = 4 – 1 = 3

Probability value at 0.05 or 5% = 7.81

The chi-square value of 25.43 is greater than the critical value of 7.81. We can reject null hypothesis. Hence the two traits are linked and the ratio, 1:1:1:1 as expected is not possible.

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