Torque Lab help
I need to find the Mass of the meter stick (mms) using the equation
(M1+mmc)g(Xo-X1)=(M2+mmc)*g*(X2-Xo)+mms*g*(Xcm-Xo)
xo= 03.m
mmc= 0.01516kg
m1=0.3kg
x1=0.01m
m2= 0.470
x2= 0.4m
xcm= 0.495m
Torque Lab help I need to find the Mass of the meter stick (mms) using the...
Consider a meter stick of negligible mass. In a statics experiment, 3 masses are attached to the meter stick. Mass m1 = 120 gm pulling up at position x1 =10 cm and angle 1 = 110, mass m2 = 260 gm pulling up at position x2 =30 cm and angle 2 = -100, mass m3 = 150 gm pulling up at position x3 =15 cm and angle 3 = 15. Let the x-axis coincide with the long axis of the...
at With the meter stick on the support stand, suspend a gram mass m = 100g the 15-cm mark on the meter stick. Then adjust the lever arm for a gram mass m2 = 200g on the other side of the axis. See Figure. X axis X X2 m m2 Record the mass and position x as read on the meter stick and then record the lever arms. Compute the torques and find a percent difference between the clockwise (Tow)...
Place an unknown mass at the 10 cm mark of the meter stick. Suspend from the other side a counter mass m2 = 300g and adjust its position until the system is in static equilibrium. Using, Στ = 0 calculate the unknown mass m². Remove the unknown mass and determine its mass on the laboratory balance. See Figure. This is the accepted mass. Calculate % error. % Error lexperimentalacceptedy 100 accepted X axis X X2 m m, m=? X =...
How do I find Torque, such as what the last column is asking? ase 2(a) Total Mass (g) Moment arms (cm) Torque ig cm t (CCW) x1 Xo mu m2 m, Show your calculation here:
Procedure 1, 2, 3 Mass of a clamp: 21.5 True mass of meter stick: _133.6 g Center of mass of meter stick: _50 cm True weight of unknown mass: _212.99_ Procedure 4 Position of the 100-g mass: 10.0 cm Position of equilibrium: _30.9 cm Mass of the stick from method of torques: Procedure 5 Position of the 100-g mass: 10.0 cm Position of the 200-g mass: _90.0 cm Position of equilibrium of meter stick: Procedure 6 Position of unknown mass...
A) Find the moment of inertia of a 2 meter long stick with a mass of 14 kg, if it is spun about the center of the stick B) Find the rotational kinetic energy of a spinning (not rolling) bowling ball that has a mass of 7 kg and a radius of 0.10 m moving at 7 m/s. HINT: v = rω C) An ice skater with a moment of inertia of 10 kg m2 spinning at 19 rad/s extends...
A uniform wooden meter stick has a mass of m = 799 g. A clamp can be attached to the measuring stick at any point Palong the stick so that the stuck can rotate freely about point P, which is at a distance d from the zero-end of the stick as shown. Part (a) Calculate the moment of inertia in kg-m of the meter stick if the pivot point P is at the 50-cm mark. Part (b) Calculate the moment of inertia...
Please help thank you! Three masses are attached to a uniform meter stick, as shown in the figure. The mass of the meter stick is 0.5 kg and the masses to the left of the fulcrum are m = 4.4 kg and m2 = 4.8 kg. Find the mass my need to be attached to the right end of the stick to balance the system - 30 cm 40 cm - 30 cm A wheel rotates without friction about a...
Can I get help with these Physics Pre Lab questions? Please answer all the questions to the best of your ability if you can thank you! Ppte side of the fulcrum so that it balances the system ehboset ever arm is significantly different from the unknown mass lever arm). 0Wh mass such that its is signi ecord the known mass and both lever arms in table 3. epeat steps 17 and 18 with a different known mass. 18. R 19....
I am asked to derive equation (6) by using diagram 6. Please show me how with step-by-step. PHYS 1111L/2211L Predicting an Equilibrium Position In our third procedure, we will hang two masses from the meter stick and use the equilibrium principle to predict where the support must be placed so that the system will balance. The set-up is illustrated in Diagram 6. 300 cm 65.0 em X1 x, X Wi Diagram 6 This time we will place two specified masses,...