X ~ Eponential ()
Where = 1 / 4
We have to calculate P( X <= 3) = ?
P( X <= x) = e-X
So,
P( no more than 3 years without requiring repair) = 1 - e-3/4
= 1- 0.4724
= 0.5276
On average, a certain kind of kitchen appliance requires repairs once every four years. Assume that...
Problem 10: 10 points Assume that the distribution of the lifetime of a certain appliance is given. Knowing that the device has served five years, find the chance that it will serve 5 more years 1. Assume that the lifetime, T, is exponentially distributed, with the mean equal to 25 years. 2. How will your answer change if the lifetime (T) is uniformly distributed over the interval, (0,25)?
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2- On the average, a certain type of laptop works effectively for nine years. The length of time this certain laptop works effectively is exponentially distributed a) (5%) What is the probability that a the laptop work effectively more than 6 years? b) (8%) Eighty percent of computer parts last at most how long?
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2. On the average, a certain type of laptop works effectively for nine years. The length of time this certain laptop works effectively is exponentially distributed. a) (5%) What is the probability that a the laptop work effectively more than 6 years? b) (8%) Eighty percent of computer parts last at most how long?
2- On the average, a certain type of laptop works effectively for nine years. The length of time this certain laptop works effectively is exponentially distributed. a) (5%) What is the probability that a the laptop work effectively more than 6 years? b) (8%) Eighty percent of computer parts last at most how long?
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