Question

At an urgent care facility, patients arrive at an average rate of one patient every 6 minutes (that is λ-6). Assume that the

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Answer #1

a)P(X<4)=1-e-x/\lambda =1-e-4/6 =0.4866

b)pth percentile =-\lambdaln(1-p)

hence 75th percentile =-6*ln(1-0.75)=8.318 minute

c)expected number of patients in 30 minutes=30/6=5

hence from Poisson distribution ; more than 6 patients arrive during a half-hour period= P(X>6)=1-P(X<=6)

=1-\sum_{x=0}^{6}e^{-5}5^{x}/x! =1-0.7622 =0.2378

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