Which of the substances below will have the greatest standard molar entropy?
C4H10(g)
C4H10(l)
Xe(g)
Which of the substances below will have the greatest standard molar entropy?
C4H10(g)
C4H10(l)
Xe(g)
C4H10(g), because it is a gas and as such has translational, rotational, and vibrational modes, allowing for greater energy dispersal | |
C4H10(l), because it is a liquid, so the molecules are in close contact with one another, making the dispersal of energy more efficient | |
Xe, because it has the greatest molar mass | |
C4H10(g) and C4H10(l) will have the same, greatest, standard molar entropy because they have the same molar mass and molecular complexity. |
C4H10(g), because it is a gas and as such has translational, rotational, and vibrational modes, allowing for greater energy dispersal |
Butane in liquid state -- Standard molar entropy 229.7 J/(mol K)
Butane in gas state -- Standard molar entropy 310.23 J/(mol K)
Xe in gas state -- Standard molar entropy 169.7 J K-1mol-1
So highest Standard molar entropy will be for Butane in gas state, so option 1 will be correct
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