Question

A large block P attached to a light spring execute

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Answer #1

when the acceleration of block P exceeds the max possible acceleration of the block B that can be generated by the force of the friction.

using newton's law of motion for block P-

kx = Ma

a = kx/M ...............1

this acceleration must be equal to acceleration produced in block B as -

\mumg = ma

a = \mug ........................2

from equation 1 and 2 -

kx/M = \mug

for maximum amplitude x = a

w = [k/M]0.5

[2\pi*1.60]0.5 = k/M

k/M = 101.06

101.06 a = 0.510*9.8

a = 0.049 m

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