3)
given
L = 7.6 cm = 0.076 m
d = 33 cm = 0.33 m
I = 3 A
B = 2.5 kG = 2.5*10^3*10^-4 = 0.25 T
a) let n is the number of turns per unit length.
we know, B = mue*n*I
==> n = B/(mue*I)
= 0.25/(4*pi*10^-7*3)
= 66314 turns/m
b) length of single loop of wire = 2*pi*r
= 2*pi*(d/2)
= 2*pi*(0.33/2)
= 1.037 m
c) no of turns in the given in the solenoid, N = n*L
= 66314*0.076
= 5040 turns
length of the wire needed = N*1.037
= 5040*1.037
= 5226 m
Third Test, Page 4 of 6 Nov 7, 2016 3. To construct a solenoid, you wrap...
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