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For a given reaction, AH is 111 kJ and AS is -249 J/K. At what temperatures is the reaction spontaneous? A. T< 446 K B. None.
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Answer #1

Ans- T> -446 K

We have ∆G = ∆H - T∆S.

For spontaneous process ∆G<0

So ∆H/∆S < T

Therfore ∆H/∆S = 111000/-249 K= -446K.

Therefore T> -446 K for spontaneous reaction

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