Question

1. Adiabatic Processes in Orographic Lifting (8 points total) me figure on the next page. Imagine a parcel of air moving over the mountains from the West to east. T. (air temperature) and T (dew point temperature) are given at the start. 3.T, " 1 2000 m . C le) / 1500 m 4. T. _"C 1000 m T = 28 "c T-18°c 2.T. - T = 12°C Sierra Nevada Omse level) Rocky Mountains 1. What is the elevation the LCL (lifting condensation level) for the Sierra Nevada? Why? (1 point) 2. What is the air temperature at the top of the Sierra Nevada at Location 1 (2000 m)? Why? (1 point) 3. What is the air temperature at the bottom of the valley at Location 2 (2000 m)? Given this air temperature and the known dew-point temperature (12°C). what is the relative humidity at this location? (Hint: Convert both temperatures to °F and round up to integer; then reference to the saturation vapor pressure table to solve the problem) (2 points) Location 2 (2000 m)? Given thies location? (Hint: Cockhown dew-point temperature (1 Page 4

i need help with 1-6 and there is also 4 questions on the graph

Answer 1

1. LCL height = 125(T-Tdp)

For Sieara Nevada LCL = 125(28- 18) = 125*10 = 1250 m

The elevation of lifted condensation level is 1250 m above sea level.

2.Considering the dry adiabatic lapse rate (DALR) = 9.8oC/ 1000 m; and

moist adiabatic lapse rate (MALR) = 5oC/ 1000 m

Temperature decreases till LCL as per DALR and beyond that as per MALR.

So, till 1250 m

T = 28oC - ((9.8/1000)*1250)oC = (28- 12.25) oC = 15.75 oC

After 1250 m till 2000 m

T = 15.75oC - ((5/1000)*750)oC = (15.75-3.75)oC = 12oC

Air temperature at location 1 = 12oC

3.On the leeward side air descend (increases) as per DALR, so,

air temperature at location 2 = 12oC + 9.8oC = 21.8oC

Tdp (at location 2) = 12oC

Relative humidity at location 2 = 100-5(T-Tdp) = 100-5(21.8-12) = 100-(5*9.8) = 100-49 = 51%

4. LCL for moving from location 2 to location 3 = 125(21.8-12) = 125*9.8 = 1225 m

Which means LCL for moving from location 2 to 3 will be 1000 m + 1225 m = 2225 m

Till 2225 m the temperature will decrease as per DALR and beyond that as per MALR.

So, till 2225 m

T = 21.8oC - ((9.8/1000)*1225)oC = 21.8oC-12.005oC = 9.795oC

From 2225 m to 3000 m

T = 9.795oC - ((5/1000)*775)oC = 9.795oC - 3.875oC = 5.92oC

So, the final air temperature at location 3 will be 5.92oC.

5.On the leeward side air descend (increases) as per DALR, so,

the air temperature at location 4 = 5.92oC + ((9.8/1000)*1500)) = 5.92oC+14.7oC = 20.62oC

6.From location 1 towards location 2 and from location 3 towards location 4 is most likely to experience a rain shadow desert as both are on the leeward sides of the mountains.