Question

With a near point of 12.0 cm, a nearsighted technician can focus on relatively nearby objects. Yet, with a far point 58.0 cm out, he cannot clearly see distant objects without optical aid.

(a) Calculate the focal length (in cm) of a contact lens that would enable this technician to clearly view very distant objects. (Hint: Allow p to approach infinity in the thin-lens equation).

(b) What power (in diopters) describes this contact lens?

(c) When this contact lens is in use, what is the technician's near point (in cm)?

(d) Which statement best describes the consequences of correcting distance vision, when it comes to viewing nearby objects?

Contacts or glasses for nearsightedness make it easier to see very close objects, too.

Contacts or glasses for nearsightedness have no effect upon how you see very close objects.    

Contacts or glasses for nearsightedness make it harder to see very close objects.

Answer 1

las (b f = -58 cm Pata 1 = -1.72 Diopter co Let near point be, object distance = - image distance, v= - 12 am using lens equation. f + t = { 7 I t 1 = u= 15-1 cm -12 (d)

Contacts or glasses for nearsightedness make it harder to see very close objects.