The single slit diffraction pattern shown below was made with light with λ = 420 nm....
The single slit diffraction pattern shown below was made with light with λ = 420 nm. The screen was 1.7 m from the slit, and the distance to the second minimum (indicated by the arrow) was 0.5 cm. What is the slit width in mm?
Homework Answers
The width of the second minimum can be determined as :
d = 2L*sin(alpha)
where L=1.7 m is the distance between the slit and screen and alpha
is the angle for direction to the first minimum. Because
sin(alpha) = lambda/a,
d = 2L*lambda/a = 2*1.7*420x10^-9/0.005 = 0.0002856 m = 0.02856
cm.
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