for the following first-order reaction, what would be the rate at 2 Molarity concentration of N2O5 if the rate constant is 4.8×10^-3 s^-1.
2N2O5 (soln)->4NO2 (soln)+O2 (soln)
for the following first-order reaction, what would be the rate at 2 Molarity concentration of N2O5...
The decomposition of N2O5 in solution in carbon tetrachloride proceeds via the reaction: 2N2O5 (soln) → 4NO2 (soln) + O2 (soln) The reaction is first order and has a rate constant of 4.82 x 10-3 s-1 at 64 oC. The reaction is initiated with 0.058 mol in a 1.25 L vessel. What is the half-life of the reaction?
6) The rate constant for the first-order decomposition of N2O5 in the reaction 2N2O5(g) → 4NO2(g) + O2(g) is k=3.38 x 10-5 s-1 at 25°C. What is the half-life of N2O5? What will be the total pressure, initially 88.3 kPa for the pure N2O5 vapour, (a) 10 s, (b) 10 minutes after initiation of the reaction?
The decomposition of N2O5 in carbon tetrachloride proceeds as follows: 2N2O5→4NO2+O2 The rate law is first order in N2O5. At 64*C the rate constant is 4.82 ×10^−3s^−1 The rate law is 4.82x10-3s-1 [N2O5] The rate of rxn when [N2O5]=2.40x10^-2 M is 1.16x10^-4 M/s What happens to the rate when the concentration of N2O5 is doubled? What about halved? The answers are NOT 9.64x10^-3 and 2.41x10^-3 M/s
The decomposition of N2O5 in carbon tetrachloride proceeds as follows: What is the rate of reaction when N205] = 0.0270? Express the rate in molarity per second to three significant figures. 2N2O3 + 4NO2 + O2 The rate law is first order in N2O5. At 64 °C the rate constant is 4.82 x 10-3 3-1 IV AP R O 2 ? You may want to reference (Pages 576 - 581) Section 14.3 while completing this problem. rate = M /S...
The first-order rate constant for the decomposition of N2O5, 2N2O5(g)→4NO2(g)+O2(g) at 70∘C is 6.82×10−3 s−1. Suppose we start with 2.30×10−2 mol of N2O5(g) in a volume of 1.5 L . a. How many moles of N2O5 will remain after 6 min ? b. How many minutes will it take for the quantity of N2O5 to drop to 1.9×10−2 mol ? c. What is the half-life of N2O5 at 70∘C?
The first-order rate constant for the decomposition of N2O5, 2N2O5(g)→4NO2(g)+O2(g) at 70∘C is 6.82×10−3 s−1. Suppose we start with 2.00×10−2 mol of N2O5(g) in a volume of 2.0 L . How many moles of N2O5 will remain after 7.0 min? How many minutes will it take for the quantity of N2O5 to drop to 1.6×10−2 mol? What is the half-life of N2O5 at 70∘C?
The first-order rate constant for the decomposition of N2O5, 2N2O5(g)→4NO2(g)+O2(g) at 70∘C is 6.82×10−3 s−1. Suppose we start with 2.40×10−2 mol of N2O5(g) in a volume of 2.1 L. a) How many moles of N2O5 will remain after 7.0 min? b) How many minutes will it take for the quantity of N2O5 to drop to 1.6×10−2 mol?
Write a balanced reaction for which the following rate relationships are true: Rate = -1/2 delta[N2O5] over delta t = 1/4 delta[NO2] over delta t = delta]O2] over delta t a. 2N2O5 yields 4NO2 + O2 b. 4NO2 + O2 yields 2N2O5 c. 2N2O5 yields NO2 + 4O2 d. 1/4 NO2 + O2 yields 1/2 N2)5 e. 1/2 N2O5 yields 1/4 NO2 + O2 Can someone please describe WHY the answer is A? Please show work.
The first-order rate constant for the decomposition of N2O5, 2N2O5(g)→4NO2(g)+O2(g) at 70∘C is 6.82×10−3 s−1. Suppose we start with 2.60×10−2 mol of N2O5(g) in a volume of 2.3 L Part A How many moles of N2O5 will remain after 4.0 min ? Part B How many minutes will it take for the quantity of N2O5 to drop to 1.8×10−2 mol ? Part C What is the half-life of N2O5 at 70∘C?
The first-order rate constant for the decomposition of N2O5, 2N2O5(g)→4NO2(g)+O2(g) at 70∘C is 6.82×10−3 s−1. Suppose we start with 2.50×10−2 mol of N2O5(g) in a volume of 1.8 L . Part A: How many moles of N2O5 will remain after 4.0 min ? Part B: How many minutes will it take for the quantity of N2O5 to drop to 1.9×10−2 mol ? Part C: What is the half-life of N2O5 at 70∘C?