Question

6.5.34 A pair of dice is rolled 240 times. What is the probability that a total of 7 occurs (a) at least 36 times? (b) between 50 and 56 times inclusive? (c) exactly 40 times? Click here to view page 1 of the standard normal distribution table Click here to view page 2 of the standard normal distribution table. (a) The probability is (Round to four decimal places as needed.)

Answer 1

Given nz 240. total of 7 occurs (1,6) (2,5) (3,4) (4,3) (5,2) (6, 1) P - 6 36 6 240* * - 40 mean = m*p = 2400 standard deviatios oa Inpq to all 40 5 200/6 5,773503 a atleast 36 P(x > 36) 36-40 P-MP р 5.773503 -4 5.773503 1 - P(Z < -0.69282) 1 -0.244211 - 0.755789 P(x>36) 0.7558

between 50 and 56 inclusive) P(30< p< 56) p-Mp < Plot 50-40 56-40 5-773503 5-773503 -planen 16 << 5.773503 5.773503 p (1-73205122 <2-771281) - P(222-771281) - Pf2<1-732054) 0.997208 -0.958368 0.03884 0.0388 P(50<p (56)

n-1 P (x= 30), m= 240, p=%, x= 30 P(x:x) = m plane me ph(1-4)" P(x= 36): 240 16 30 (1-2) 240 (+) (3) 240-30 30 30 240 30 0.0154