a mass of .50kg is attached to the end of a spring with constant k=15n/m if...
a mass of .50kg is attached to the end of a spring with constant k=15n/m if the mass is pulled out .10m beyond the equilibrium position and released from rest, how fast will it be , moving when It crosses back through the equilibrium position
Homework Answers
Solution:
Using conservation of energy principal,
K.E = S.P.E
1/2mv2 = 1/2kx2
v2 = kx2/m
= 15*0.12/0.5
= 0.55 m/s.
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