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a mass of .50kg is attached to the end of a spring with constant k=15n/m if...

a mass of .50kg is attached to the end of a spring with constant k=15n/m if the mass is pulled out .10m beyond the equilibrium position and released from rest, how fast will it be , moving when It crosses back through the equilibrium position

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Answer #1

Solution:

Using conservation of energy principal,

K.E = S.P.E

1/2mv2 = 1/2kx2

v2 = kx2/m

= 15*0.12/0.5

= 0.55 m/s.

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