Question

Please explain and show steps, thanks!

2. By doing a nuclear diffraction experiment you measure the de Broglie wavelength of the proton to be 9.00 fm. (a) What is the speed of the proton? (b) Through what potential difference must it be accelerated to achieve this speed?

Answer 1

The speed of the proton is v = h/m lambda = 6.626 times 10^- 34/(1.67 times 10^- 27) (9.00 times 10^15) = 4.4085 times 10^7 m/s The potential difference is Delta V = h^2/22 mq lambda^2 = -(6.626 times 10^34)^2/2(1.67 times 10^27) (1.60 times 10^19) (9.00 times 10^15)^2 = 1.104 times 10^7 V