Question

To initiate a nuclear reaction, a nuclear physicist wants to shoot a proton into a 5.65-fm-diameter ¹²C nucleus. The proton must impact the nucleus with a kinetic energy of 4,000 keV. Assume the nucleus remains at rest.

(a) With what speed must the proton hit the target?

(b) Through what potential difference must the proton be accelerated from rest to acquire this speed?

Answer 1

kg aj let u be the speed of proton m=1625x10-27 Kinetic energy | mv2 4000 x103 x 16810-19 box 116725 X75-2v? V=2.7668107 mis a 2.77 1107 mis 6) det au be the potential difference ep= 16 X1019 charge then Aux. ep= 4000 x103x 1.6*10-19 Ava uxlo 6 volt → charge on proton