Question

Part a is right, but part b is wrong.

By doing a nuclear diffraction experiment, you measure the de Broglie wavelength of a proton to be 9.46 fm. (a) What is the speed of the proton? 0.139 (b) Through what potential difference must it be accelerated to achieve that speed? 9.18

By doing a nuclear diffraction experiment, you measure the de Broglie wavelength of a proton to be 9.46 fm.

(a) What is the speed of the proton?
  c

(b) Through what potential difference must it be accelerated to achieve that speed?
MV

Answer 1

Using the conservation of energy q Delta v = change in k middot E i.e q Delta v = 1/2 mv^2 Delta v = 1/2 times mv^2/q = 1/2 times 1.67 times 10^-27 times (0.133 times 3 times 10^8)^2/1.6 times 10^-13 Delta v = 9.0748 times 10^6 volt = 9.07 Mv Delta v = 9.07 mass we can calculate it using lambda = h/ squareroot 2cm middot 1/ squareroot v Therefore lambda = 6.6 times 10^-34/ squareroot 2 times 16. Times 1.67 times 10^-27 -19 middot 1/ squareroot v = 9.46 times 10^-15 2.85503 times 10^-11/ squareroot v = 9.46 times 10^-15 lambda = 9.09 mv