A proton is accelerated through a potential difference of 25,000V. What is the de Broglie wavelength of the proton(in m)?
A. 5.9*10^12
B. 6.8*10^12
C.6.5*10^12
D.18*10^12
E. 5.5*10^12
A proton is accelerated through a potential difference of 25,000V. What is the de Broglie wavelength...
Through what potential difference must a proton be accelerated for it to have a de Broglie wavelength of 0.55 pm?
Show that the de Broglie wavelength of an electron accelerated from rest through potential difference of V volts is 1.226/squareroot V nm.
An electron is accelerated from rest through a difference of potential V. a) Show that the de Broglie wavelength, in unit of angstrom Å (10-10 m), for a non- relativistic electron accelerated through a small potential difference is: λ =12.27/(v)^1/2 b) Calculate λ if the electron is accelerated through 50 V. c) Find the de Broglie wavelength for a relativistic electron that is accelerated from rest through a large difference potential difference at a modern particle collider. d) Show that...
Item 11 An electron is accelerated from rest through a potential difference of 190 V. Part A What is the de Broglie wavelength of the electron?Item 12 An electron has de Broglie wavelength 2.81x10-10 m. Part A Determine the magnitude of the electron's momentum p.
An electron has a de Broglie wavelength λ = 3.9 10-10 m. (a) What is its momentum? _____ kg·m/s (b) What is its speed? _____ m/s (c) Through what voltage difference does it need to be accelerated to reach this speed? _____ V (d) What's the speed of a 50 kg person having a de Broglie wavelength of λ = 4.4e-38 m? _____ m/s
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A proton in a particle accelerator is accelerated using voltage 6.53x106 v. Calculate the de Broglie wavelength of this proton in femtometers (fm, 1 fm = 10-15 m). = 1.01e-25 X fm
10. Show the ratio of the Compton wavelength to the de Broglie wavelength for a relativistic electron with Energy E is given by 소 11. Non-relativistic electrons and protons are accelerated from rest though the same potential difference Δ V, show the ratio of their de Broglie wavelengths is given by: 弖
Determine the wavelength of an electron that has been accelerated through a potential difference of 100V (Hints:) 1. Kinetic energy T=.5 mv2 2. For an electron .511 MeV=mc2=E 3. Energy is conserved 4.The de Broglie idea of wave-particle duality states h/p where p is momentum and h is Planck's constant
A)A proton is accelerated from rest through a potential difference of 25707 V. What is the kinetic energy of this proton after this acceleration? The mass of a proton is 1.673 × 10−27 kg and the elemental charge is 1.602 × 10−19 C. Answer in units of J. B) What is the speed of the proton after this acceleration? Answer in units of m/s.