Question 17 1 pts Given these half cell reactions: Zn+2 (aq) + 2e → Zn (s)...
Given are two half-cells, described by the equations: Zn^(2+)(aq) + 2e- -> Zn(s) E(standard) = -0.76 V Ag^(+)(aq) + e- -> Ag(s) E(standard) = +0.80 V A. Write down the net equation for the spontaneous reaction that takes place in the cell. B. Draw the two half cells and mark the anode and the cathode. C. Mark the solutions' concentration necessary in order to reach the standard potential. D. How will the cell's potential be influenced by the addition of...
Use the half-reactions below to produce a voltaic cell with the given standard cell potential. Standard Cell Potential Co- (aq) + e-Cot (aq) E = +1.82 V 1.53 V 2H(aq) + 2e-H2(g) E = +0.00 V Pb2+ (aq) + 2e-Pb(s) E = -0.13 V Fe (aq) + e-Fel+ (aq) E = +0.77 V Ag (aq) + e-Ag(s) E = +0.80 V Sn* (aq) + 2e Sne (aq) 20.13 V Cu- (aq) + e- Cu(aq) E = +0.15 V Zn²+ (aq)...
Reaction Eo Ag+(aq)+ e-→ Ag(s) 0.80V Zn2+(aq)+ 2e-→Zn(s) -0.76V What would be the cathode reactant in the Voltaic Cell made from the half-reactions above? Question options: a. Zn2+(aq) b. Ag+(aq) c. Ag(s) d. Zn(s)
Consider the following reaction. 2Ag^+(aq) + Zn(s) --> 2Ag(s) +Zn(aq) a) write the individual oxidation and reduction half-reactions, specifying which is the anode and which is the cathode reaction. b) calculate the cell potential for a cell containing 0.10M Ag^+ and 0.25M Zn^2+ at 298K. (E ag= 0.80 V and E zn= -0.76 V)
Separate galvanic cells are made from the following half-cells: cell 1: H+(aq)/H2(g) and Pb2+(aq)/Pb(s) cell 2: Fe2+(aq)/Fe(s) and Zn2+(aq)/Zn(s) Which of the following is correct for the working cells? Standard reduction potentials, 298 K, Aqueous Solution (pH = 0): Cl2(g) + 2e --> 2C1-(aq); E° = +1.36 V Fe3+(aq) + e --> Fe2+(aq); E° = +0.77 V Cu2+(aq) + 2e --> Cu(s); E° = +0.34 V 2H+(aq) + 2e --> H2(g); E° = 0.00 V Pb2+(aq) + 2e --> Pb(s);...
What is the anode of the voltaic cell made by the combination of following half reactions? Reaction Standard Reduction Potential Zn2+ + 2e– → Zn E0 = –0.76 V Ag+ + e– → Ag E0 = +0.80 V Question options: a. Zn2+(aq) b. Ag+(aq) c. Ag(s) d. Zn(s)
Consider a voltaic cell where the anode half-reaction is Zn(s) → Zn2+(aq) + 2 e− and the cathode half-reaction is Sn2+(aq) + 2 e– → Sn(s). What is the concentration of Sn2+ if Zn2+ is 2.5 × 10−3 M and the cell emf is 0.660 V? The standard reduction potentials are given below Zn+2(aq) + 2 e− → Zn(s) E∘red == −0.76 V Sn2+(aq) + 2 e– → Sn(s) E∘red −0.136 V
Consider the galvanic cell based on the following half-reactions: Zn2+ + 2e + Zn * = -0.76 V Cd²+ + 2e - → Cd &* = -0.40 V a. Determine the overall cell reaction and calculate call (Use the lowest possible coefficients. Use the pull-down boxes to specify states such as (aq) or (s). If a box is not needed, leave it blank.) V cell b. Calculate AG and K for the cell reaction at 25°C. AGE kJ K =...
Half-Reaction Fe2+(aq) + 2e Fe(s) Hg2+ (aq) + 2e Hg() Ag+ (aq) + e + Ag(s) Cu2+ (aq) + 2e + Cu(s) Zn2+ (aq) + 2e → Zn(s) E (V) -0.44 0.86 0.80 0.34 - 0.76 Using the table, calculate Eºcell for the following electrochemical cell under standard conditions voltmeter a) 1.24 V Fe. salt bridge Ag b) -1.24 V c) 2.04 V d) - 2.04 V Ag a b С
Consider the voltaic cell and reduction half potentials: Zn(s) | Zn 2+(aq) (0.100 M) || Ni2+(aq) (1.50 M) | Ni(s) Zn 2+ (aq)/Zn (s) E o = - 0.760 V Ni2+ (aq)/Ni (s) E o = - 0.230 V a) Sketch the voltaic cell represented with the above line notation. Label the anode and cathode and indicate the half-reactions occurring at each electrode and the species present in each solution. Also indicate the direction of electron flow (3 marks). b)...