Question

Cdi. Cabe Show ALL Work for Credit with correct number of significant figures, rounding and units. Fill in the Molecular Orbital energy diagram 1. Describe the relations between electran pair geometrics and Hybridization nota- What is the using the Boud Order for the N MO diagram? 2. Label excl bood as a sigma or pi bood, and the determice tbe tal umber signs and pi boods. Thea for each cabo atom: determine the hybridization and the electron prir greinilemekculu huluw. H-C=C-CEN NI 11 3. True False and explain why Tribe valence bond Treatment, 1 hund is lima when two 20 orbitals overlap side to side. 4. Answer the following questions for the Nz homomclear diatonic molecule. What is the electron configuration for one of the nitrogen atoms? Druw the Lewis Dot Structure for X, What is the Electron Pair Geometry using VSEPR" What is the Molenlar Cirometry using VSEPR? What is the libridization of the Neatom in N? - Search о не е

Answer 1

1. Relationship ble Elochan Pair Geometries and Hybridisation Natation No of Bond Paix No. of Love Pain Told Electron Pair Molecular Geometry Hybridisation Linear 2 3 4 2 2 3 sp3 5 3 4 5 6 7 o sp Trigonal Plonnay sp? Tetrahedral Trigonal bipyramidal 'sp²d Octahedral Pentagonal bipylonidal sped 5 6 sp3d² 7 2) N AUTI H 6 Total bonds = Sigma Total pie bonds = 3

2 for Carbon C-1 = attached to 3 sigma bonds. 3 election pairs sp = Tridonal Plannar for Carbon C=2 attached to 3 sigma bonds - 3 election pairs sp? bimeed Trigonal Planner For Carbon C=3 attached to a sigma bondy I election pair = sp Linear. = 4. Electronic configuration of N ( z=7) 152 25 2p = 15² 25² epi pj 2133 7N Lewis Dot structure Na N=N No. of valence election for N = 5 NS EN: According to VSEPR, Ng molecular falls under the Category of AB type. sp hybr Lingay molecular geometry ( Each Notom has 5 valence election and neads 3 more to complete its Triple bond between 2 Nihoyon atoms and semaining 4 Valence election as lone pair). bridisation octet. i. a

> Moleadar Geometry using VSEPR will be Linear, with bond angle 180 (One triple bond and one lone pair accounts regions of election density. Therefore sp hybridischio for two 2/2 Ng 710 个个个 22 2p IL 11025 1V 25 25 25 1 is IV Is TS 11 N = 15 25 px py 22 23 Bond Order 2 NA = No. of Bonding elections 2 (No-Na) ( 10 - 4 Na="" Anti Bording I) 2 B.O g = 3 N=N
question number 3 is not clear. wheher asking for which bond .

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