Question

An information technology analyst believes that they are losing customers on their website who find the checkout and purchase system too complicated. She adds a one-click feature to the website to make it easier, but finds that only about 6% of the customers are using it. She decides to launch an ad awareness campaign to tell customers about the new feature in the hope of increasing the percentage. She doesn't see much of a difference, so she hires a consultant to help her. The consultant selects a random sample of recent purchases, tests the hypothesis that the ads produced no change against the alternative that the percent who use the one-click feature is now greater than 6%, and finds a P-value of 0.61. What conclusion is appropriate? Which conclusion is appropriate? O A. There is a 39% chance that the ads worked. O B. There is a 61% chance that natural sampling variation could produce poll results like these if there's really no change in website use. O C. There is a 61% chance that natural sampling variation could produce poll results like these if the use of the one-click feature has increased. OD. There is a 61% chance that the ads worked. O E. There is a 61% chance that the null hypothesis is true.

Answer 1

solution :- P-value = 0.61 Ho: p=0.06 Ha:p 30.06 tur) so) 1 B There is 61 % chance that natural Sampling rasiation could produce poll result like these if there is really no change in website use