Question

Return a version of the given string, where for every star (*) in the string the star and the chars immediately to its left and right are gone. So "ab*cd" yields "ad" and "ab**cd" also yields "ad".

starOut("ab*cd") → "ad"
starOut("ab**cd") → "ad"
starOut("sm*eilly") → "silly

Provided statement:

public String starOut(String str) {

//code goes here  

}

  

Answer 1

public String starOut(String str) {
    String result = "";
    for(int i = 0; i < str.length(); ++i) {
        if(!(str.charAt(i) == '*' || (i != 0 && str.charAt(i-1) == '*') || (i != str.length()-1 && str.charAt(i+1) == '*'))) {
            result += str.charAt(i);
        }
    }
    return result;
}

$\color{red}Below\;one\;is\;the\;complete\;program\;if\;you\;are\;interested..$

public class StarOut {

    public String starOut(String str) {
        String result = "";
        for(int i = 0; i < str.length(); ++i) {
            if(!(str.charAt(i) == '*' || (i != 0 && str.charAt(i-1) == '*') || (i != str.length()-1 && str.charAt(i+1) == '*'))) {
                result += str.charAt(i);
            }
        }
        return result;
    }

    public static void main(String[] args) {
        StarOut starOut = new StarOut();
        System.out.println(starOut.starOut("ab*cd"));
        System.out.println(starOut.starOut("ab**cd"));
        System.out.println(starOut.starOut("sm*eilly"));
    }

}