Question

Java Python Warmup-2 > string_times prev next | chance Given a string and a non-negative int n, return a larger string that is n copies of the original string. string_times('Hi', 2) – 'HiHi' string_times('Hi', 3) - 'HiHiHi' string_times('Hi', 1) – 'Hi' Solution: Go Save, Compile, Run (ctrl-enter) Show Solution def string_times (str, n): def string_times(str, n): result = "" for i in range(n): # range(n) is [0, 1, 2, .... n-1] result = result + str # could use t= here return result
This CSIS 9 Python.

Answer 1

def string_times (str,n): return n str def extra end(str): endTwo = str[-2] + str[-1] return 3 endTwo def make_tags(tag, word): open Tag '<'+tag+'>' closeTag '</'+tag+'>' return (openTag+word+closeTag) def combo_string(a,b): if len(a) > len(b): return ba+b elif len(a) < len(b): return a+b+a

Warmup-2 > string_times

A better solution for printing a string for n number of times is by taking advantage of built in mechanisms in python.

Eg - In python if str='a' and str1 = 4*str then str1 would store the vale 'aaaa' we use this mechanism for solving the problem in a cleaner way.

Code:

def string_times(str,n):
    return n*str

String-1 > extra_end

To index strings from the end we use negative indexes in python i.e. in str='tank', str[-1] would give us the last character in the string 'k', similaly str[-2] would be 'n'.

We create a string by taking the last two characters and using the string_times mechanism return a string with 3 copies.

Code:

def extra_end(str):
   endTwo = str[-2] + str[-1]
   return 3*endTwo

String-1 > make_tags

We create the two tags openTag and closeTag by using string concatenation. And then return a string word by concatenating the string openTag at the front and closeTag at the end.

Code:

def make_tags(tag, word):
   openTag = '<'+tag+'>'
   closeTag = '</'+tag+'>'
   return (openTag+word+closeTag)

String-1 > combo_string

In this problem we first check with an if statement if the length of string a is more and enclose it within string b(using string concatenation like in previous problems) if the condition is true and return the string.

Else if the length of string a is less than b then we enclose the string b with a and return the value.

Code:
def combo_string(a,b):       
   if len(a) > len(b):
       return b+a+b

   elif len(a) < len(b):
       return a+b+a