Question

Logic-2 close far prev I next chance Given three ints, a b c, return True if one of b or c is "close" (differing from a by at most 1), while the other is "far", differing from both other values by 2 or more. Note: abs(num) computes the absolute value of a number. close far(1, 2, 10) True close far(1, 2, 3)False close-far(4, 1, 3) → True Go .Save, Compile, Run (ctrl-enter) def close far(a, b, c):

Here's what I need you to do. Thank you to whoever is helping me in solving this problem. Please go on CodingBat.com and look for Logic-2, close_far. Once its found, type the code in their and click on "go" to compile the code. Once again, thank you. I'm going to comment down below to let you know if the code works or not.

Answer 1

def close_far(a, b, c):
    if (abs(a-b) <= 1 and abs(a-c) > 1 and abs(b-c) > 1) or (abs(a-b) > 1 and abs(b-c) > 1 and abs(a-c) <= 1):
        return True
    else:
        return False