Given two int values, return their sum. Unless the two values are the same, then return...
This CSIS 9 Python. Java Python Warmup-2 > string_times prev next | chance Given a string and a non-negative int n, return a larger string that is n copies of the original string. string_times('Hi', 2) – 'HiHi' string_times('Hi', 3) - 'HiHiHi' string_times('Hi', 1) – 'Hi' Solution: Go Save, Compile, Run (ctrl-enter) Show Solution def string_times (str, n): def string_times(str, n): result = "" for i in range(n): # range(n) is [0, 1, 2, .... n-1] result = result + str...
in python and according to this #Creating class for stack class My_Stack: def __init__(self): self.items = [] def isEmpty(self): return self.items == [] def Push(self, d): self.items.append(d) def Pop(self): return self.items.pop() def Display(self): for i in reversed(self.items): print(i,end="") print() s = My_Stack() #taking input from user str = input('Enter your string for palindrome checking: ') n= len(str) #Pushing half of the string into stack for i in range(int(n/2)): s.Push(str[i]) print("S",end="") s.Display() s.Display() #for the next half checking the upcoming string...
python function will Return True if string x contains 3 vowels in a row, in consecutive locations, false otherwise. assuming that 'vowels' refer to the following lowercase lttrs: a,e,i,o,u programs fails partially, only allowed to use float, str, int, appen, split, strip, len, range def vowels_three(x): for i in range (o, len(x), 2): if x[i] not in ('a,e,i,o,u'): return False return True
Given a string containing space-separated integer values, compute the sum of those values. Each string will contain at least one number. sumString("1 2") → 3 sumString("1 2 3") → 6 sumString("7 -7 0 59") → 59 int sumString(String str) { }
/** Given an int array, return true if the array contains duplicate values. duplicateInts({3}) -> false duplicateInts({1, 2}) -> false duplicateInts({7, 7}) -> true duplicateInts({1, 2, 3, 4, 5}) -> false duplicateInts({1, 2, 3, 2, 4, 5}) -> true **/ public static boolean duplicateInts(int[] numbers) { //your code here return false; }//end duplicateInts /** Given a String array, return true if the array contains duplicate values. Note: Capital letters count duplicateStrings({"a"}) -> false duplicateStrings({"a", "b", "c", "d"}) -> false duplicateStrings({"a",...
Python: problem 1 Given an array of integers, return the sum of two indices from this array based on input parameters, x and y. Example: Given nums = [2, 7, 11, 15], x = 3, y = 1 Because nums[x] + nums[y] = 15 + 7 = 22, return 22. You may use this as a template for your code class Solution: def two_sum(self, nums: List[int], x: int, y: int) -> int:
def calculate_total(price_list: List[list]) -> int: """Return the sum of all second elements in the sublists of price_list. Precondition: price_list is a list of lists of length 2, and the second element of it sublist is an int. >>> price_list = [["apple", 1], ["sugar", 5], ["mango", 3], ... ["coffee", 9], ["trail mix", 6]] >>> calculate_total(price_list)
Consider a non-empty int array ints. A contiguous subarray ints[ start .. start + len -1 ] (with starting index start and length len) is called a flat if all elements of that subarray are equal. Furthermore, such a subarray is called a plateau if it is flat and each of the elements ints[start -1] and ints[start + len] that immediately proceed/succeed the subarray are either nonexistent (i.e., out of array’s index range) or are strictly smaller than the elements...
I need assistance with this code. Is there any way I can create this stack class (dealing with infix to postfix then postfix evaluation) without utilizing <stdio.h> and <math.h>? ____________________________________________________________________________________________ C++ Program: #include <iostream> #include <string> #include <stdio.h> #include <math.h> using namespace std; //Stack class class STACK { private: char *str; int N; public: //Constructor STACK(int maxN) { str = new char[maxN]; N = -1; } //Function that checks for empty int empty() { return (N == -1); } //Push...
def slice_list(lst: List[Any], n: int) -> List[List[Any]]: """ Return a list containing slices of <lst> in order. Each slice is a list of size <n> containing the next <n> elements in <lst>. The last slice may contain fewer than <n> elements in order to make sure that the returned list contains all elements in <lst>. === Precondition === n <= len(lst) >>> slice_list([3, 4, 6, 2, 3], 2) == [[3, 4], [6, 2], [3]] True >>> slice_list(['a', 1, 6.0, False],...